`NoneType`-使用BeautifulSoup时出错

Question

下面是我的代码。。。

from bs4 import BeautifulSoup
import requests

for count in range(1,2):

r = requests.get('http://manufacturer.indiatradepage.com/all/a_a_enterprises/' + str(count) + '/',headers={'User-Agent': 'Googlebot'})
soup = BeautifulSoup(r.text,'lxml')
data = soup.find('div',class_='container_main')
for links in data.find_all('div',class_='com_countainer'):
for link in links.find_all('a')[0:1]:
l = link['href']
r = requests.get(l)
soup = BeautifulSoup(r.text,'lxml')
data = soup.find('td',{"id":"intro_txt"})
table1 = data.find('table',{"style":"max-height: 400px !important"})
body1 = table1.find('div',class_='f_body')

table2 = data.find('div',{"id":"f3_1"})
div = table2.find('div',class_='f_body')

body2 = div.find('div',{"style":"text-transform:capitalize; "})
print body2.text + body1.text

我得到以下错误。

Traceback(上次调用(：文件"C:\Python27/indiatradepage_try.py"，第19行，在body1=table1.find('div'，class_='_body'(AttributeError："NoneType"对象没有属性"find">

由于以下错误，我的代码每次都会中断。

Answer 1

您可以通过不尝试在NoneType对象上使用属性.find来处理此问题，这是您在body1 = table1.find('div',class_='f_body')和可能在table2 = data.find('div',{"id":"f3_1"})中尝试执行的操作

您可以执行这样的操作，检查表是否为None，如果为，则打印出它不在那里，而不是.find，然后继续循环。

from bs4 import BeautifulSoup
import requests

for count in range(1,2):
r = requests.get('http://manufacturer.indiatradepage.com/all/a_a_enterprises/' + str(count) + '/',headers={'User-Agent': 'Googlebot'})
soup = BeautifulSoup(r.text,'lxml')
data = soup.find('div',class_='container_main')
for links in data.find_all('div',class_='com_countainer'):
for link in links.find_all('a')[0:1]:
l = link['href']
r = requests.get(l)
soup = BeautifulSoup(r.text,'lxml')
data = soup.find('td',{"id":"intro_txt"})
table1 = data.find('table',{"style":"max-height: 400px !important"})
if table1 != None:
body1 = table1.find('div',class_='f_body').text
else:
body1 = ' table1 no present '

table2 = data.find('div',{"id":"f3_1"})
if table2 != None:
div = table2.find('div',class_='f_body')
body2 = div.find('div',{"style":"text-transform:capitalize; "}).text
else:
body2 = ' table2 not present '
print (body2 + body1)