如何使用xsmtplib代替smtplib发送邮件.与smtplib不同，xsmtplib不要求输入登录密码

Question

根据pipy.org

使用xsmtplib的方法如下：

from xsmtplib import SMTP<br/>
server = SMTP(host="smtp.example.com", proxy_host="proxy.example.com")<br/>
server.sendmail("[e-mail]", "[e-mail]", "I have an issue. Please help!")<br/>
server.quit()

但我想先用密码登录，然后再发送
类似于：

server = xsmtplib.SMTP("smtp.gmail.com", 587)<br/>
server.ehlo()<br/>
server.starttls()<br/>
server.ehlo()<br/>
server.login("[e-mail]", "zzzzz")<br/>
message = f"Dear Sir,nnThere is a price drop for your selected product. Current Price is {price}.n Regards"<br/>
server.sendmail("[e-mail]", "[e-mail]", message)<br/>

Answer 1

要使用的答案"xsmtplib.xsmtplib.SMTP"；rest与smtplib完全相似。

server = xsmtplib.xsmtplib.SMTP("smtp.gmail.com", 587)
server.ehlo()
server.starttls()
server.ehlo()
server.login("[e-mail]", "zzzzz")<br/>
message = f"Dear Sir,nnThere is a price drop for your selected product. Current Price is {price}.n Regards"
server.sendmail("[e-mail]", "[e-mail]", message)