我使用Pycharm Text Editor
和PyCryptodome Library
使用Advanced Encryption Standard (AES)
对消息进行加密。它也是最常用的CCD_ 4之一。我的AES Encryption
代码如下:
from Crypto.Cipher import AES
key = os.urandom(16)
cipher = AES.new(key, AES.MODE_ECB)
ciphertext, tag = cipher.encrypt_and_digest(message)
我遇到了错误:-
AttributeError: 'EcbMode' object has no attribute 'encrypt_and_digest
在线路:-
ciphertext, tag = cipher.encrypt_and_digest(message)
我已经尝试卸载该模块几次了,但错误仍然存在。Pycharm
没有用红色下划线标记这条线,我可以使用ctrl-click
进入源代码,查看encrypt_and_digest()
函数是否存在。
我的问题是:-
为什么代码不能通过编译器?python中是否还有其他模块可以用于执行AES encryption
?
如果您阅读文档,您将看到encrypt_and_digest()
仅受现代模式支持:
MODE_CCM
MODE_EAX
MODE_GCM
MODE_SIV
MODE_OCB
ECB模式真的不应该用于任何事情,因为它在语义上不安全。
从Error
可以看出,encrypt_and_digest()
属性在AES Encryption
的ECB (Electronic Code Book)
模式下不可用。因此,您的查询有两种解决方案,让我们逐一查看:-
1.通过更改模式:-
通过将mode
更改为modern modes
,我们可以使用encrypt_and_digest()
模块。encrypt_and_digest()
模块基本上是encrypt()
和digest()
模块的组合。
encrypt()
:-此模块用于Encrypt
您的Message
digest()
:-此模块用于生成Message
的MAC Tag
# List of 'Modern Modes' was given below:-
1. MODE_EAX
2. MODE_CCM
3. MODE_SIV
4. MODE_GCM
5. MODE_OCB
使用EAX Mode
的给定场景的代码如下所述:-
# Import all the Important Libraries
from Crypto.Cipher import AES
import os
# 'pad_message()' function declaration for padding purpose.
# Because 'message' length should be always multiple of '16'
def pad_message(message):
while len(message) % 16 != 0:
message = message + " "
return message
# Initialization of 'Key' and 'Message'
key = os.urandom(16)
message = input("Enter your Message for AES Encryption:- ")
# If the length of the message is not multiple of '16' then pad it
message = pad_message(message)
# Print Message, Key and Length of Message before Encryption Process
print("nMessage:-", message)
print("Key:-", key)
print("Length of the Message:-", len(message))
# Declare New module for AES Encryption in 'EAX' Mode
cipher = AES.new(key, AES.MODE_EAX)
# Encrypt 'Message' and Generate 'MAC Tag' Using 'encrypt_and_digest()' method
cipher_text, mac_tag = cipher.encrypt_and_digest(message.encode('utf-8'))
# Print Encrypted Message
print("nEncryption of Message Using AES:-", cipher_text)
print("MAC Tag of our Encrypted Message is:-", mac_tag)
# Output of Above Code:-
Enter your Message for AES Encryption:- Stack Overflow
Message:- Stack Overflow
Key:- b'xf1x9axc1x12xdcI7xc8xe4xcfx1e5xe4x93ixc4'
Length of the Message:- 16
Encryption of Message Using AES:- b'x97x0e+xcb^x82xeelhs2_x90mx1c+'
MAC Tag of our Encrypted Message is:- b'c!xb2xf4x82xceT3x0cM1x04x87(y?'
2.不改变模式:-
如果要使用ECB (Electronic Code Book)
模式进行Encrypt
。则可以使用CCD_ 35和CCD_。
使用ECB Mode
的给定场景的代码如下所述:-
# Import all the Important Libraries
from Crypto.Cipher import AES
import os
# 'pad_message()' function declaration for padding purpose.
# Because 'message' length should be always multiple of '16'
def pad_message(message):
while len(message) % 16 != 0:
message = message + " "
return message
# Initialization of 'Key' and 'Message'
key = os.urandom(16)
message = input("Enter your Message for AES Encryption:- ")
# If the length of the message is not multiple of '16' then pad it
message = pad_message(message)
# Print Message, Key and Length of Message before Encryption Process
print("nMessage:-", message)
print("Key:-", key)
print("Length of the Message:-", len(message))
# Declare New module for AES Encryption in 'ECB (Electronic Codebook)' Mode
cipher = AES.new(key, AES.MODE_ECB)
# Encrypt 'Message'
cipher_text = cipher.encrypt(message.encode('utf-8'))
# Print Encrypted Message
print("nEncryption of Message Using AES:-", cipher_text)
print("Hex of Cipher Text:-", cipher_text.hex())
# Verify by decrypting Cipher Text whether you are recieving same message or not
decrypted_message = cipher.decrypt(cipher_text)
print("nDecryption of Cipher Text Using AES:-", decrypted_message)
# Output of Above Code:-
Enter your Message for AES Encryption:- Stack Overflow
Message:- Stack Overflow
Key:- b'x94x88oxf0x8fxbexecx0ex1exdfx06Axdf<xbexe3'
Length of the Message:- 16
Encryption of Message Using AES:- b'xf6c)xeexeax13xdcXx9cx06Ex82~{cxc6'
Hex of Cipher Text:- f66329eeea13dc589c0645827e7b63c6
The decryption of Cipher Text Using AES:- b'Stack Overflow
希望此解决方案能帮助您。