如何更新数组中的嵌套对象(Mongoose/MongoDB)

Question

我一直在努力解决如何使用特定id更新嵌套数组中的对象的问题。我尝试实现如下所示的$set。我希望能够使用来自请求主体的数据更新id为62ff74bfe80b11ade2d34455的任务。

{
"_id": "62fa5aa25778ec97bc6ee231",
"user": "62f0eb5ebebd0f236abcaf9d",
"name": "Marketing Plan",
"columns": [
{
"name": "todo",
"_id": "62fa5aa25778ec97bc6ee233",
"tasks": [
{           ====> here
"title": "Task Four",
"description": "This is task four",
"subtasks": [
{
"name": "wash dshes",
"completed": false,
"_id": "62ff74bfe80b11ade2d34456"
},
{
"name": "do homework",
"completed": false,
"_id": "62ff74bfe80b11ade2d34457"
}
],
"_id": "62ff74bfe80b11ade2d34455"
}
]
},
{
"name": "doing",
"_id": "62fa5aa25778ec97bc6ee234",
"tasks": []
},
{
"name": "done",
"_id": "62fa5aa25778ec97bc6ee235",
"tasks": []
}
],
"__v": 0
}

const updatedTask = await Board.findOneAndUpdate(
{
"columns.tasks._id": req.params.id,
},
{ $set: { "columns.$.tasks": req.body } },
{ new: true }
);

Answer 1

您可以将位置运算符与数组过滤器结合使用。下面是一个如何更新相关任务的特定字段的示例：

db.collection.update({
"columns.tasks._id": req.params.id
},
{
"$set": {
"columns.$[].tasks.$[t].title": "it works"
}
},
{
"arrayFilters": [
{
"t._id": req.params.id
}
]
})

你也可以在mongoplayground上试试这个。

如果你正在寻找一种方法来替换匹配的任务对象本身，你可以这样做：

db.collection.update({
"columns.tasks._id": req.params.id
},
{
"$set": {
"columns.$[].tasks.$[t]": req.body
}
},
{
"arrayFilters": [
{
"t._id": req.params.id
}
]
})