这个python代码将一直打印相同的语句，直到控制台关闭，我该如何修复它

Question

所以，我为学校做了一个调查，我必须制作一个程序，用调查中的信息打印有多少人选择了第二个问题的第三个选项(c(。然后我不得不根据调查数据打印出参加调查的人数。然后我不得不问他们想要查看哪个问题的结果。如果他们输入的数字不在1、2、3的范围内，则应该打印"0"；这不是问题"然后返回到相同的代码：

choice = int(input("Which question's results would you like to see? "))

但它只是继续打印"；这不是一个问题"一次又一次，直到系统关闭我的控制台。这是我的全部代码：

print ("1 person that took the survey said they like C (sandwich)")
print ("7 people took the survey")
choice = int(input("Which question's results would you like to see? "))
while choice not in [1,2,3]: print ("That isn't a question!")
choice = int(input("Which question's results would you like to see? ")

如果你想知道我说的是什么调查，你可以在这里找到：https://docs.google.com/forms/d/e/1FAIpQLSdvKS6JsLzT4_bIkMOq6IOIn1c_1tsCG78bm4f4rr_5P75rMA/viewform?usp=sf_link

Answer 1

因为您永远不会退出while语句，所以永远不会更新选项值，代码应该是：

print ("1 person that took the survey said they like C (sandwich)")
print ("7 people took the survey")
choice = int(input("Which question's results would you like to see? "))
while choice not in [1,2,3]: 
print ("That isn't a question!")
choice = int(input("Which question's results would you like to see? "))

Answer 2

尝试这个轻微的修改：

print ("1 person that took the survey said they like C (sandwich)")
print ("7 people took the survey")
choice = None
while choice not in [1, 2, 3]:
choice = int(input("Which question's results would you like to see? "))
print ("That isn't a question!")