Python split()函数说明

Question

我对Python非常陌生，我只是想了解一些事情。

我得到了一堆要打开的txt文件，其中包含数千个单词，所有单词都用空格分隔，我相信我已经在下面的代码中介绍过了。。但我只是想知道如何将这些行分解为3个块或用户输入的一些int？

来自['perfect', 'dealing', 'crave', 'stirring', 'expedition', 'alexandria', 'vanish', 'dealing', 'crave']

至[['perfect', 'dealing', 'crave'], ['stirring', 'expedition', 'alexandria'],['vanish', 'dealing', 'crave']]

甚至返回到列表形成

a
b
c

TIA-

word_list=[]
filename = "filename.txt"
with open(filename,"r") as file_object:
for line in file_object:
word_list=line.split()
print(word_list)
return(word_list)

Answer 1

使用itertools配方中的grouper构造：

def grouper(iterable, n, fillvalue=None):
"Collect data into fixed-length chunks or blocks"
# grouper('ABCDEFG', 3, 'x') --> ABC DEF Gxx"
args = [iter(iterable)] * n
return zip_longest(*args, fillvalue=fillvalue)

你的代码是：

word_list = []
n = 3
filename = "filename.txt"
with open(filename, "r") as file_object:
for line in file_object:
word_list.append(grouper(line.split(), n))
return word_list

Answer 2

您可以使用for i in range(0, len(word_list), 3)在间隔为3的列表上迭代，并使用索引对原始列表进行切片

new_list = [word_list[i:i+3] for i in range(0, len(word_list), 3)]
# [['perfect', 'dealing', 'crave'], ['stirring', 'expedition', 'alexandria'], ['vanish', 'dealing', 'crave']]

Answer 3

您不是在更新word_list，而是在重写它的值，它应该是这样的。

word_list=[]
filename = "filename.txt"
with open(filename,"r") as file_object:
for line in file_object:
word_list.append(line.split()) # notice this
print(word_list)
return(word_list)
sub_list_size = 3; # take from user input or as needed
output = [word_list[i: i+sub_list_size] for i in range(0, len(word_list), sub_list_size)]
print(output)