multi_vowel_words函数返回具有3个或更多连续元音(a、e、i、o、u)的所有单词.为此，请填充正则表达式

Question

import re
def multi_vowel_words(text):
pattern = r"b(?=[a-z]*[aeiou]{3})[a-z]+b"
result = re.findall(pattern, text)
return result
print(multi_vowel_words("Obviously, the queen is courageous and gracious."))
# Should be ['Obviously', 'queen', 'courageous', 'gracious']

我得到的输出：-['queen', 'courageous', 'gracious']帮助我用正确的模式获得所需的输出

Answer 1

我会保持简单，并在不区分大小写的模式下匹配模式bw*[aeiou]{3}w*b：

def multi_vowel_words(text):
return re.findall(r'bw*[aeiou]{3}w*b', text, flags=re.IGNORECASE)
inp = "Obviously, the queen is courageous and gracious."
words = multi_vowel_words(inp)
print(words)  # ['Obviously', 'queen', 'courageous', 'gracious']

Answer 2

您可以更轻松地捕获模式前后的字母。

pattern = r'(w*.[a,e,i,o,u]{2,}w*)'

Answer 3

此正则表达式模式r"\b[\w][aeou]{3，}[\w]">将匹配具有3个或3个以上连续元音的单词{3，}，包括以大写字母\b[\w]*开头的单词

import re
def multi_vowel_words(text):
pattern = r"b[w]*[aeiou]{3,}[w]*"
result = re.findall(pattern, text)
return result
print(multi_vowel_words("Obviously, the queen is courageous and gracious.")) 
# ['Obviously', 'queen', 'courageous', 'gracious']