如何获得每次迭代的响应,就像实时流提要一样?
这是RestAPImain.py:
from fastapi import FastAPI
from fastapi import Request
from fastapi import WebSocket
import asyncio
app = FastAPI()
@app.get("/ws_res")
async def websoc(websocket: WebSocket):
await websocket.accept()
for i in range(100000):
i = "John"
await asyncio.sleep(0.01)
await websocket.send_json({"msg": i})
await websocket.close()
现在,我正试图从python代码中获得响应,但我收到一个错误,上面写着Unsupported upgrade request.
以下是API方面的输出:
INFO: Started server process [67680]
INFO: Waiting for application startup.
INFO: Application startup complete.
INFO: Uvicorn running on http://127.0.0.1:8000 (Press CTRL+C to quit)
WARNING: Unsupported upgrade request.
下面是我用来访问API(test.py
(的python代码:
import asyncio
import websockets
async def hello():
uri = "ws://127.0.0.1:8000/ws_res"
async with websockets.connect(uri) as websocket:
greeting = await websocket.recv()
print(f"< {greeting['msg']}")
asyncio.get_event_loop().run_until_complete(hello())
Traceback (most recent call last):
File "test.py", line 12, in <module>
asyncio.get_event_loop().run_until_complete(hello())
File "/usr/lib/python3.8/asyncio/base_events.py", line 616, in run_until_complete
return future.result()
File "test.py", line 7, in hello
async with websockets.connect(uri) as websocket:
File "/home/test/env/lib/python3.8/site-packages/websockets/client.py", line 517, in __aenter__
return await self
File "/home/test/env/lib/python3.8/site-packages/websockets/client.py", line 542, in __await_impl__
await protocol.handshake(
File "/home/test/env/lib/python3.8/site-packages/websockets/client.py", line 296, in handshake
raise InvalidStatusCode(status_code)
websockets.exceptions.InvalidStatusCode: server rejected WebSocket connection: HTTP 400
Fastapi websocket端点需要使用websocket
装饰器而不是get
装饰器来定义:
@app.websocket("/ws_res")
async def websoc(websocket: WebSocket):
await websocket.accept()
for i in range(100000):
i = "John"
await asyncio.sleep(0.01)
await websocket.send_json({"msg": i})
await websocket.close()
有关详细信息,请参阅文档:https://fastapi.tiangolo.com/advanced/websockets/