这个代码给了我一年中所有的月份和数字.我怎么能让数字不一样呢

Question

month = ["January", "February", "March", "April", 
"May", "June", "July", "August", "September", 
"October", "November", "December"]
num = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31]
for i in range(len(month)):
for h in range(len(num)):
print(month[i], "the", num[h])

我怎样才能把数字定为有些月是28号，有些月是31号？目前所有的月份都截止到31号。

Answer 1

以下是我在坚持基本解决问题的方式的同时如何解决问题：

month = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]
month_days = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
is_leap_year = True
for i in range(len(month)):
for h in range(29 if (month_days[i] == 28 and is_leap_year) else month_days[i]):
print(month[i], "the", h + 1)

请注意，实际上没有必要在列表中列出每天的数字。另外，看看我是如何应对闰年的。它将在2月is_leap_year == True时增加一天。