我真的无法摆脱这个。
我在树视图中有树视图项。树视图项包含带有内容的复选框。我如何得到的内容,并把它放在一个列表。目前我得到了这个
foreach (TreeViewItem item in treeView1.Items)
{
foreach (TreeViewItem childItem in item.Items)
{
CheckBox checkBoxTemp = childItem.Header as CheckBox;
if (checkBoxTemp == null) continue;
optieListBox.Items.Add(checkBoxTemp.Content);
}
}
我不确定我是否正确理解你的问题,但你可以试试这个
foreach (TreeViewItem childItem in item.Items)
{
CheckBox cbx = null;
//finds first checkbox
foreach(object child in childItem.Items){
cbx = child as CheckBox;
if (cbx != null) break;
}
ctrList.Items.Add(cbx.Content);
}
将TreeView绑定到一个集合。这样,您就不必操纵UI组件来访问数据,而是直接访问数据。
另一种方法是通过递归:在类级别声明optieListBox列表并调用GetContainers()方法作为入口点调用。optieListBox列表应该给你在树视图中所有选中项的内容列表。
List<string> optieListBox = new List<string>();
private List<TreeViewItem> GetAllItemContainers(TreeViewItem itemsControl)
{
List<TreeViewItem> allItems = new List<TreeViewItem>();
for (int i = 0; i < itemsControl.Items.Count; i++)
{
// try to get the item Container
TreeViewItem childItemContainer = itemsControl.ItemContainerGenerator.ContainerFromIndex(i) as TreeViewItem;
// the item container maybe null if it is still not generated from the runtime
if (childItemContainer != null)
{
allItems.Add(childItemContainer);
List<TreeViewItem> childItems = GetAllItemContainers(childItemContainer);
foreach (TreeViewItem childItem in childItems)
{
CheckBox checkBoxTemp = childItem.Header as CheckBox;
if (checkBoxTemp != null)
optieListBox.Items.Add(checkBoxTemp.Content);
allItems.Add(childItem);
}
}
}
return allItems;
}
private void GetContainers()
{
// gets all nodes from the TreeView
List<TreeViewItem> allTreeContainers = GetAllItemContainers(this.objTreeView);
// gets all nodes (recursively) for the first node
TreeViewItem firstNode = this.objTreeView.ItemContainerGenerator.ContainerFromIndex(0) as TreeViewItem;
if (firstNode != null)
{
List<TreeViewItem> firstNodeContainers = GetAllItemContainers(firstNode);
}
}
试试这个:
List<string> values = new List<string>;
foreach (string node in treeView.Nodes)
{
values.Add(node);
}
//Loop through nodes
另外,如果树视图的节点有子节点(节点),请尝试这样做:
List<string> values = new List<string>;
//Called by a button click or another control
private void getTreeValues(Object sender, EventArgs e)
{
foreach (string node in treeView.Nodes)
{
TreeNode child = (TreeNode)child;
values.Add(node)
getNodeValues(child);
}
foreach (string value in values)
{
Console.WriteLine(value + "n");
}
}
//Recursive method which finds all children of parent node.
private void getNodeValues(TreeNode parent)
{
foreach (string child in parent.Nodes)
{
TreeNode node = (TreeNode)child;
values.Add(child);
if (nodes.Nodes.Count != 0) getNodeValues(child);
}
}