如何构建JQuery滑块与方形子弹

Question

我已经在jquery中构建了一个简单的滑块。它工作正常。但是现在我想高亮显示滑块底部的方形，因为每个图像都改变了。

我的代码在这里。

我使用了以下html代码:

<div>
<div class="slider">
<span class="control_next">Next</span>
<span class="control_prev">Previous</span>
<ul>
<li style="background:#ccc;">Image 1</li>
<li style="background:#547;">Image 2</li>
<li style="background:#124;">Image 3</li>
<li style="background:#054;">Image 4</li>
</ul>
</div>
<div class="square square1"></div>
<div class="square square2"></div>
<div class="square square3"></div>
<div class="square square4"></div>
</div>

上面的代码

.slider {
  position: relative;
  overflow: hidden;
  border: 1px solid #ccc;
}
.slider ul {
  position: relative;
  margin: 0;
  padding: 0;
  list-style: none;
}
.slider ul li {
  position: relative;
  display: block;
  float: left;
  margin: 0px;
  padding: 0;
  width: 500px;
  height: 150px;
  color
}
.control_prev, .control_next {
 position: absolute;
  bottom: 0;
  z-index: 999;
  display: block;
  padding: 5px;
  width: auto;
  height: auto;
  background: #2a2a2a;
  color: #fff;
  text-decoration: none;
  font-size: 18px;
  opacity: 0.8;
  cursor: pointer;
  margin:5px;
}
.control_prev:hover, .control_next:hover {
  opacity: 1;
  -webkit-transition: all 0.2s ease;
}
.control_prev {
  right:50;
  border-radius: 0 2px 2px 0;
}
.control_next {
  right: 0;
  border-radius: 2px 0 0 2px;
}
.square
{
  z-index: 999;
  height:20px;
  width:20px;
  background:#ccc;
  position: relative;
  float: left;
  margin:0px 5px; 
}

而用于滑动图像的jquery是

$(document).ready(function(){
var slideCount = $('.slider ul li').length;
var slideWidth = $('.slider ul li').width();
var slideHeight = $('.slider ul li').height();
var sliderUlWidth = slideCount * slideWidth;
$('.slider').css({ width: slideWidth, height: + slideHeight });
$('.slider ul').css({ width: sliderUlWidth, marginLeft: - slideWidth });
$('.slider ul li:last-child').prependTo('.slider ul');
function moveLeft() {
    $('.slider ul').animate({
        left: + slideWidth
    }, 700, function () {
        $('.slider ul li:last-child').prependTo('.slider ul');
        $('.slider ul').css('left', '');
    });
};
 function moveRight() {
    $('.slider ul').animate({
        left: - slideWidth
    }, 700, function () {
        $('.slider ul li:first-child').appendTo('.slider ul');
        $('.slider ul').css('left', '');
    });
};
$('.control_prev').click(function () {
    moveLeft();
});
$('.control_next').click(function () {
    moveRight();
});
$(function(){
setInterval(function () {
    moveRight();
}, 5000);
});
});

请帮我完成这个。谢谢。

Answer 1

您需要跟踪当前显示的图像，然后相应地为"squares"添加一个类:http://jsfiddle.net/WZCA3/

//additional variables
var allSquares = $('.square');
var totalSquares = allSquares.length;
var index = 0;
//the move function
function moveRight() {
    index++;
    $('.slider ul').animate({
        left: - slideWidth
    }, 700, function () {
        $('.slider ul li:first-child').appendTo('.slider ul');
        $('.slider ul').css('left', '');
    });
     setSquare();
};
// the active status
function setSquare() {
    allSquares.removeClass("active").eq(index % totalSquares).addClass("active");   
}

点击jsfiddle链接查看完整代码。

基本上索引变量跟踪当前显示的图像。当滑块移动到下一个图像时，它增加1，当滑块移动到上一个图像时，它减少1。每次你改变图像，你得到当前的索引，并找到它对应的"正方形"通过设置currentIndex % numberOfImages，在你的例子中，这将始终是一个0到3之间的值，始终设置正确的正方形