有没有办法将密码文本从句点(.(更改为星号(*(。
密码正在编辑文本中输入。
<EditText
android:id="@+id/passWord1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:gravity="center"
android:inputType="number"
android:password="true"/>
在xml文件中插入编辑文本
<EditText
android:id="@+id/passWordEditText"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:gravity="center"
android:inputType="textPassword"/>
然后你的类文件继续从edittext中获取findViewById,并为此实现
EditText edittext = (EditText)findViewById(R.id.passWordEditText);
edittext.setTransformationMethod(new AsteriskPasswordTransformationMethod());
这个类实现了
public class AsteriskPasswordTransformationMethod extends PasswordTransformationMethod {
@Override
public CharSequence getTransformation(CharSequence source, View view) {
return new PasswordCharSequence(source);
}
private class PasswordCharSequence implements CharSequence {
private CharSequence mSource;
public PasswordCharSequence(CharSequence source) {
mSource = source; // Store char sequence
}
public char charAt(int index) {
return '*'; // This is the important part
}
public int length() {
return mSource.length(); // Return default
}
public CharSequence subSequence(int start, int end) {
return mSource.subSequence(start, end); // Return default
}
}
};
如果你的代码是Kotlin,那么你必须制作单独的java文件,然后你必须将java与Kotlin代码一起使用
<EditText
android:id="@+id/passWord1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:gravity="center"
android:inputType="textPassword"//here is the change. check it once in your xml
android:password="true"/>
在eclipse中,当您在android:inputType
处移动光标时,单击Ctrl+Space时会有提示。然后您可以看到选项列表。在那里你可以选择textPassword
如果您想用*
代替.
,请检查此Android: Asterisk Password Field
通过Ram kiran 发布的链接得到了答案
text.setTransformationMethod(new AsteriskPasswordTransformationMethod());
public class AsteriskPasswordTransformationMethod extends PasswordTransformationMethod {
@Override
public CharSequence getTransformation(CharSequence source, View view) {
return new PasswordCharSequence(source);
}
private class PasswordCharSequence implements CharSequence {
private CharSequence mSource;
public PasswordCharSequence(CharSequence source) {
mSource = source; // Store char sequence
}
public char charAt(int index) {
return '*'; // This is the important part
}
public int length() {
return mSource.length(); // Return default
}
public CharSequence subSequence(int start, int end) {
return mSource.subSequence(start, end); // Return default
}
}
};
Kotlin
class AsteriskPasswordTransformationMethod : PasswordTransformationMethod() {
override fun getTransformation(source: CharSequence, view: View): CharSequence {
return PasswordCharSequence(source)
}
inner class PasswordCharSequence (private val source: CharSequence) : CharSequence {
override val length: Int
get() = source.length
override fun get(index: Int): Char = '*'
override fun subSequence(startIndex: Int, endIndex: Int): CharSequence {
return source.subSequence(startIndex, endIndex)
}
}
}
以Kotlin方式:
类星号PasswordTransformationMethod:PasswordTransformationMethod(({
override fun getTransformation(source: CharSequence?, view: View?): CharSequence {
return super.getTransformation(source, view)
}
abstract inner class PasswordCharSequence(val source: CharSequence) : CharSequence {
override val length: Int
get() = source.length
override fun get(index: Int): Char =
'*'
override fun subSequence(start: Int, end: Int): CharSequence {
return source.subSequence(start, end) // Return default
}
}
}`
EditText.setTransformationMethod(new PasswordTransformationMethod());
对于android:inputType,有一种类型的密码。
试试这个
android:inputType="textPassword"