在PHP中搜索多维数组中的值并获得父数组

Question

我有这样一个数组:

Array
(
    [0] => Array
        (
            [name] => Dick Jansen
            [matchedMovie] => Array
                (
                    [0] => Array
                        (
                            [nameMovie] => Saw
                            [genre] => Horror
                            [patheMovie] => Texas Chainsaw 3D
                            [patheMovieGenre] => Horror
                            [score] => 100.00
                        )
                )
        )
    [1] => Array
        (
            [name] => Jim Scott
            [matchedMovie] => Array
                (
                    [0] => Array
                        (
                            [nameMovie] => Shooter
                            [genre] => Action, Thriller
                            [patheMovie] => The Shining
                            [patheMovieGenre] => Horror, Suspense/Thriller 
                            [score] => 52.38
                        )
                    [1] => Array
                        (
                            [nameMovie] => Resident Evil Movie
                            [genre] => Action/Horror
                            [patheMovie] => Texas Chainsaw 3D
                            [patheMovieGenre] => Horror
                            [score] => 63.16
                        )
                )
        )
)

我想搜索[patheMovie]值(如'The Shining')，并获得父数组与[name]加上只有[matchedMovie]数组与匹配的[patheMovie]返回。

我试过这样做:

$search='Texas Chainsaw 3D';
                $sorted=false;
                foreach ($sorted as $n=>$c)
                    if (in_array($search,$c)) {
                        $cluster=$n;
                    break;
                }

例如，如果我搜索'The Shining'，我希望数组像这样返回:

    Array
    (
    [0] => Array
            (
                [name] => Dick Jansen
                [nameMovie] => Saw
                [genre] => Horror
                [patheMovie] => Texas Chainsaw 3D
                [patheMovieGenre] => Horror
                [score] => 100.00
            )
    )
and if you search for 'Texas Chainsaw 3D' like so:
Array
    (
        [0] => Array
            (
                [name] => Dick Jansen
                [nameMovie] => Saw
                [genre] => Horror
                [patheMovie] => Texas Chainsaw 3D
                [patheMovieGenre] => Horror
                [score] => 100.00
             )
         [1] => Array
             (
                [name] => Jim Scott
                [nameMovie] => Resident Evil Movie
                [genre] => Action/Horror
                [patheMovie] => Texas Chainsaw 3D
                [patheMovieGenre] => Horror
                [score] => 63.16
              )
      )

Answer 1

这个解将依赖于两个共轭环。

<?php
function searchIt($arr, $searchItem){
$result = array();
$resultIndex = 0;
for ($i =0; $i < count($arr); $i++){
 for ($j = 0; $j < count($arr[$i]['matchedMovie']); $j++){
  if ($arr[$i]['matchedMovie'][$j]['patheMovie'] == $searchItem){
   $result[$resultIndex]['name'] = $arr[$i]['name'];
    foreach ($arr[$i]['matchedMovie'][$j] as $key => $value){
     $result[$resultIndex][$key] = $value;
   }
    $resultIndex++;
  }
 } 
}
return $result;
}
?>

<<h3> phpfiddle演示/h3>

Answer 2

还没有测试过，但这应该可以工作:

function findYourGuy($array, $searchTerm) {
    $searchTerm = 'The Shining'; // testing purpose only
    foreach($array as $personArray) {
        $matchedMovies = $personArray['matchedMovie'];
        $name = $personArray['name'];
        foreach($matchedMovies as $matchedMovie) {
            if($matchedMovie['patheMovie'] == $searchTerm) {
                return array('name' => $name, 'matchedMovie' => $matchedMovie)
            }
        }
    }
    return false; //no result
}

Answer 3

我将使用array_filter。

$movieName = 'The shining';
$result = array_filter($movies, filterCallback);
function filterCallback($var)
{
  foreach($var['matchedMovie'] as $movie) {
    if($movie['PatheMovie'] == $movieName) {
      return true;
    }
  }
}