如何在android中发送post数据和检索响应体

Question

代码工作找到，但它没有返回正确的HTTPRESPONSE它应该返回成功!而是返回一些胡言乱语。这是我的代码，请帮助我，我尝试了这么多的事情，但没有发生，请建议。

       public class PingServerActivity extends Activity {
   private Button btn6;
    //private EditText value;
     protected String name;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_ping_server);
    btn6 = (Button) findViewById(R.id.btn_6);
    //value = (EditText) findViewById(R.id.textV5);
    pingButton();
}
public void pingButton() {
    btn6.setOnClickListener(new OnClickListener() {
        @Override
        public void onClick(View v) {
            // this button would send the request to the server
            new PingPostTask().execute(new String[] {name}); 
        }
    });
}
private class PingPostTask extends AsyncTask<String, Void, String>{
     @Override
        protected String doInBackground(String... params)   
        {           
            BufferedReader inBuffer = null;
            String url = "http://ec2-54-243-205-92.compute-1.amazonaws.com/Tests/ping.php";
            String result = "fail";
            try {
                HttpClient httpClient = new DefaultHttpClient();
                HttpPost request = new HttpPost(url);
                List<NameValuePair> postParameters = new ArrayList<NameValuePair>();
                postParameters.add(new BasicNameValuePair("Password", "EGOT"));
                UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(
                        postParameters);
                request.setEntity(formEntity);
                HttpResponse response = httpClient.execute(request);//btw, i'm NOT very sure if this will work LOL
                       result = response.toString();
            } catch(Exception e) {
                // Do something about exceptions
                result = e.getMessage();
            } finally {
                if (inBuffer != null) {
                    try {
                        inBuffer.close();
                    } catch (IOException e) {
                        e.printStackTrace();
                    }
                }
            }
            return  result;
        }
        protected void onPostExecute(String result)
        {       
            //textView.setText(page); 
            Toast toast = Toast.makeText(getApplicationContext(), result, Toast.LENGTH_LONG);
          toast.show();
        }

}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.ping_server, menu);
    return true;
}

}

Answer 1

您不能简单地将HTTPResponse转换为String，您需要将其读入输入流或类似的，给出

替换:

result = response.toString();

result = EntityUtils.toString(response);

。

Answer 2

响应在某些时候不仅是字符串类型，它也可以是二进制，我建议您应该从inputstream

检索内容

HttpEntitiy entitiy = response.getEntity();
Inputstream inputstream = entitiy.getContent();
//do what you want, e.g. convert to string or decode as bitmap