从文本文件中获取特定列到数组中

Question

我需要实现的是从包含两列双精度数的文本文件中导入数据，如下所示:

201.0176    1.06E+03
201.7557    1.11E+01
202.0201    2.02E+02
202.2064    9.76E+00
202.8342    1.11E+01
203.0161    2.02E+02
203.1638    9.61E+00
203.3843    1.13E+01

这些数据多达50,000行。我希望每一列被导入到一个单独的数组，但我不能找出如何识别单独的列之间。我尝试了以下操作:

public class CodeTests {
    public static ArrayList assignArray(String filePath) throws FileNotFoundException {
        Scanner s = new Scanner(new File(filePath));
            ArrayList<Double> list = new ArrayList<Double>();
            while (s.hasNext()){
                list.add(s.nextDouble());
            }
            s.close();
            return list;
    }
    public static void main(String[] args) throws IOException {
        /*
         * 
         */
        ArrayList arrayMZ;
        arrayMZ = assignArray("F:/Stuff/Work/Work from GSK/From Leeds/ja_CIDFragmenter/testFile.txt");
        for(int i = 0; i < arrayMZ.size(); i++)
            System.out.println(arrayMZ.get(i));
        System.out.println("End");
    }
}

从运行这个我得到输出:

run:
201.0176
1060.0
201.7557
11.1
202.0201
202.0
202.2064
9.76
202.8342
11.1
203.0161
202.0
203.1638
9.61
203.3843
11.3
End
BUILD SUCCESSFUL (total time: 1 second)

谁能帮我把这些列分成两个数组，甚至分成一个单独的二维数组，在数组[0]的列下，其中有第一列数据，数组[1]中有第二列数据。例如:

  [0]         [1]
201.0176    1.06E+03
201.7557    1.11E+01
202.0201    2.02E+02
202.2064    9.76E+00
202.8342    1.11E+01
203.0161    2.02E+02
203.1638    9.61E+00
203.3843    1.13E+01

我已经尽我所能把这件事说清楚了，但如果还有什么问题，请告诉我。

谢谢

Answer 1

你可以这样做:

public static ArrayList[] assignArray(String filePath) throws FileNotFoundException {
    Scanner s = new Scanner(new File(filePath));
        ArrayList[] list = new ArrayList[2];
        ArrayList<Double> col1 = new ArrayList<Double>();
        ArrayList<Double> col2 = new ArrayList<Double>();
        while (s.hasNext()){
            String[] data = s.nextLine().split("\s+"); 
            col1.add(Double.parseDouble(data[0]));
            col2.add(Double.parseDouble(data[1]));
        }
        s.close();
        list[0] = col1;
        list[1] = col2;
        return list;
}

Answer 2

类似于

for(int i = 0; i < arrayMZ.size() / 2; i+=2)
    System.out.printf("%.4ft%En", arrayMZ.get(i), arrayMZ.get(i + 1));