用户界面——在Applescript中，我试图激活Seamonkey中的菜单项

Question

我是Applescript的新手。我做了一些搜索和阅读，发现了一些应该为激活菜单项工作的东西:

on do_menu(app_name, menu_name, menu_item)
    try
        -- bring the target application to the front
        tell application app_name
            activate
        end tell
        tell application "System Events"
            tell process app_name
                tell menu bar 1
                    tell menu bar item menu_name
                        tell menu menu_name
                            click menu item menu_item
                        end tell
                    end tell
                end tell
            end tell
        end tell
        return true
    on error error_message
        return false
    end try
end do_menu
-- In my case I want to start Seamonkey and open the Composer window (and select it) so I
-- do:
do_menu("SeaMonkey", "Windows", "Composer")

当我运行时，事件日志窗口显示:

tell application "SeaMonkey"
    activate
end tell
tell application "System Events"
    click menu item "Composer" of menu "Windows" of menu bar item "Windows" of menu bar 1 of process "SeaMonkey"
        --> error number -1728 from «class mbri» "Windows" of «class mbar» 1 of «class prcs» "SeaMonkey"
end tell

结果:假

我不知道我做错了什么

Answer 1

错误号-1728似乎是AppleScript中一个通用的"not found"错误。我在SeaMonkey中没有看到Windows菜单，但我确实看到了Window菜单。试着从Windows中去掉"s"。

另外，我认为你可能需要启用"辅助设备访问"才能使"点击"工作，如果你需要的话，你会得到一个错误消息。

Answer 2

@mu太短了，正确吗?从"Windows"中去掉"s"，它就可以工作了。如果你不想使用处理程序，下面是精简版。

activate application "SeaMonkey"
tell application "System Events"
    tell process "SeaMonkey"
        click menu item "Composer" of menu 1 of menu bar item "Window" of menu bar 1
    end tell
end tell