自定义回溯输出

Question

当存在未捕获的异常时，我使用以下代码写入.log文件:

import sys
import traceback
def uncaught_exc_handler(ex_cls, ex, tb):
   with open('mylog.log', 'w') as f: 
      traceback.print_last(file=f)
sys.excepthook = uncaught_exc_handler
1/0

输出示例:

Traceback (most recent call last):
  File "C:UsersAbcDesktoptest.py", line 11, in <module>
    1/0
ZeroDivisionError: integer division or modulo by zero

如何自定义日志记录并使用这个:

ERROR 11 (test): ZeroDivisionError: integer division or modulo by zero

?

(注意:11是发生错误的行号，test是当前文件)

PS:我想解析这4行，在第二行搜索"行"，提取附近的int等，但这是一个相当肮脏的方法，我想这不会健壮地工作

Answer 1

我相信这是你需要的:

import sys
import traceback
def uncaught_exc_handler(ex_cls, ex, tb):
    last_traceback = (traceback.extract_tb(tb))[-1]
    line_number = last_traceback[1]
    file_name = last_traceback[0].split(".")[0]
    class_name = ex_cls.__name__
    with open('mylog.log', 'w') as f: 
        f.write("ERROR %s (%s) %s: %sn" % (line_number, file_name, class_name, str(ex)))
sys.excepthook = uncaught_exc_handler

1/0

生成一个包含以下行的文件(mylog.log):

ERROR 15 (test) ZeroDivisionError: integer division or modulo by zero