如何将日期时间字符串转换为当前区域性日期时间字符串

Question

我在美国英语文化中有一个字符串说"12/1/2011"，我当前的机器文化是英国英语，是"dd/mm/yyyy"格式。如何将12/1/2011转换为1/12/2011。我试过下面的格式。

System.DateTime.Parse(result,System.Threading.Thread.CurrentThread.CurrentCulture)
              .ToString(System.Threading.Thread.CurrentThread.CurrentCulture.DateTimeFormat.ShortDatePattern)

但是我看不到任何输出。

-Lokesh .

Answer 1

DateTimeFormatInfo usDtfi = new CultureInfo("en-US", false).DateTimeFormat;
DateTimeFormatInfo ukDtfi = new CultureInfo("en-GB", false).DateTimeFormat;
string result = Convert.ToDateTime("12/01/2011", usDtfi).ToString(ukDtfi.ShortDatePattern);

^^

Answer 2

这个适合我:

string myTime = DateTime.Parse("12/1/2011")
                        .ToString(CultureInfo.GetCultureInfo("en-GB").DateTimeFormat.ShortDatePattern);

Answer 3

var culture = new CultureInfo( "en-GB" );
var dateValue = new DateTime( 2011, 12, 1 );
var result = dateValue.ToString( "d", culture ) );

Answer 4

DateTime dateValue;
CultureInfo culture = CultureInfo.CurrentCulture;
DateTimeStyles styles = DateTimeStyles.None;
DateTime.TryParse(datetimestring,culture, styles, out dateValue);

Answer 5

public static DateTime ConvertDateTime(string Date)
    {
        DateTime date=new DateTime();                        
        try
        {
            string CurrentPattern = Thread.CurrentThread.CurrentCulture.DateTimeFormat.ShortDatePattern;                
            string[] Split = new string[] {"-","/",@"","."};
            string[] Patternvalue = CurrentPattern.Split(Split,StringSplitOptions.None);
            string[] DateSplit = Date.Split(Split,StringSplitOptions.None);
            string NewDate = "";
            if (Patternvalue[0].ToLower().Contains("d") == true && Patternvalue[1].ToLower().Contains("m")==true && Patternvalue[2].ToLower().Contains("y")==true)
            {
                NewDate = DateSplit[1] + "/" + DateSplit[0] + "/" + DateSplit[2];
            }
            else if (Patternvalue[0].ToLower().Contains("m") == true && Patternvalue[1].ToLower().Contains("d")==true && Patternvalue[2].ToLower().Contains("y")==true)
            {
                NewDate = DateSplit[0] + "/" + DateSplit[1] + "/" + DateSplit[2];
            }
            else if (Patternvalue[0].ToLower().Contains("y") == true && Patternvalue[1].ToLower().Contains("m")==true && Patternvalue[2].ToLower().Contains("d")==true)
            {
                NewDate = DateSplit[2] + "/" + DateSplit[0] + "/" + DateSplit[1];
            }
            else if (Patternvalue[0].ToLower().Contains("y") == true && Patternvalue[1].ToLower().Contains("d")==true && Patternvalue[2].ToLower().Contains("m")==true)
            {
                NewDate = DateSplit[2] + "/" + DateSplit[1] + "/" + DateSplit[0];
            }
            date = DateTime.Parse(NewDate, Thread.CurrentThread.CurrentCulture);
        }
        catch (Exception ex)
        {
        }
        finally
        {
        }
        return date;
    }

Answer 6

这对我有用，

DateTimeFormatInfo usDtfi = new CultureInfo("en-US", false).DateTimeFormat;
DateTimeFormatInfo ukDtfi = new CultureInfo("en-GB", false).DateTimeFormat;
string result = Convert.ToDateTime("26/09/2015",ukDtfi).ToString(usDtfi.ShortDatePattern);