分隔范围并将数组传递给函数的方法是什么?

Question

我有attachmentList和

数组

如果我这样做

len(attachmentList) 

结果为199930;我想每次发送999个元素到api_request(附件)函数

所以伪代码是这样的

count=0
for (i=0,i<len(attachmentList),i++)
     count++
     if count=999:
       api_request(attachmentList[i-999:i])
       count=0

for循环是怎么写的呢?或者有其他的解决方案

Answer 1

使用grouper配方:

def grouper(iterable, n, fillvalue=None):
    "Collect data into fixed-length chunks or blocks"
    # grouper('ABCDEFG', 3, 'x') --> ABC DEF Gxx
    args = [iter(iterable)] * n
    return izip_longest(fillvalue=fillvalue, *args)

然后:

for chunk in grouper(attachmentList, 1000):
    api_request(chunk)

Answer 2

你可以循环999个块:

for i in range(0, len(attachmentList), 999):
    api_request(attachmentList[i:i+999])

Answer 3

可以使用range(...)函数:

previous = 0
for i in range(999,len(attachmentList),999):
    api_request(attachmentList[previous:i]
    previous = i