joined table INSERT statement

Question

我有3个表。Tbl_info、tbl_training和tbl_infotraining，其中tbl_infotraining用于连接Tbl_info和tbl_training。

tbl_training接受多个复选框值。tbl_trainings包含:

+------+-----------+
|  id  |  training |
+------+-----------+

tbl_infotrainings包含:

+------+-----------+---------------+
|  id  |  info_id  |  training_id  |
+------+-----------+---------------+

我的问题是在插入新信息时。以下是我使用的代码:

用于插入tbl_info的id(工作正常)

$sql3 = "INSERT INTO tbl_infotrainings (info_id) (SELECT id FROM tbl_info)";

插入tbl_training(has errors)的id

$sql4 = "INSERT INTO tbl_infotrainings (training_id) (SELECT id FROM tbl_trainings)";

数据库中期望的输出是:

+------+-----------+------------+
|  id  |  info_id  |  training  |
+------+-----------+------------+
|  1   |    1      |     1      |
+------+-----------+------------+
|  2   |    1      |     2      |
+------+-----------+------------+
|  3   |    1      |     3      |
+------+-----------+------------+

下面是完整的代码:

if($_POST["Submit"]=="Submit"){
$sql1="INSERT INTO tbl_info VALUES ('NULL', '$fname', '$mname', '$lname', '$street', '$barangay', '$city', '$number', '$month', '$day', '$year', '$status' , '$spouse', '$dependent')";
$result1=mysql_query($sql1);
$sql3 = "INSERT INTO tbl_infotrainings (info_id) (SELECT id FROM tbl_info)";
$result3=mysql_query($sql3);
$sql4 = "INSERT INTO tbl_infotrainings (training_id) (SELECT id FROM tbl_trainings)";
$result4=mysql_query($sql4);
    for ($i=0; $i<sizeof($checkbox);$i++){
$sql2="INSERT INTO tbl_trainings VALUES ('NULL', '".$checkbox[$i]."')";
$result2=mysql_query($sql2);    
}
}

Answer 1

不要使用'NULL'作为(我假定)AUTO_INCREMENT id的文本值-只需使用NULL关键字。

...
    $sql1 = "INSERT INTO tbl_info VALUES (NULL, '$fname', '$mname', '$lname', '$street', '$barangay', '$city', '$number', '$month', '$day', '$year', '$status' , '$spouse', '$dependent')"; // NULL not 'NULL'
    ...
    $sql2 = "INSERT INTO tbl_trainings VALUES (NULL, '".$checkbox[$i]."')"; // NULL not 'NULL'
...